18M.2.AHL.TZ1.H_1
The 3rd term of an arithmetic sequence is 1407 and the 10th term is 1183.
Find the first term and the common difference of the sequence.
[4]
a.
Calculate the number of positive terms in the sequence.
[3]
b.
Markscheme / solution
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
u1 + 2d = 1407, u1 + 9d = 1183 (M1)(A1)
u1 = 1471, d = −32 A1A1
[4 marks]
a.
1471 + (n − 1)(−32) > 0 (M1)
⇒ n <
n < 46.96… (A1)
so 46 positive terms A1
[3 marks]
b.
Examiners’ report
[N/A]
a.
[N/A]
b.