22M.1.SL.TZ1.2
The expression can be written as . Write down the value of .
[1]
a.
Hence, find the value of .
[4]
b.
Markscheme / solution
A1
[1 mark]
a.
A1A1
substituting limits into their integrated function and subtracting (M1)
OR
A1
[4 marks]
b.
Examiners’ report
Many candidates could give the value of p correctly. However, many did struggle with the integration, including substituting limits into the integrand, without integrating at all. An incorrect value of p often resulted in arithmetic of greater complexity.
a.
[N/A]
b.