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21M.2.SL.TZ1.5

pestleMathematicsAASLPaper 221M· sl-5-9-kinematics-problemssource ↗

A particle moves in a straight line. The velocity, vms-1, of the particle at time t seconds is given by v(t)=tsint-3, for 0t10.

The following diagram shows the graph of v.

Find the smallest value of t for which the particle is at rest.

[2]
a.

Find the total distance travelled by the particle.

[2]
b.

Find the acceleration of the particle when t=7.

[2]
c.
Markscheme / solution

recognising v=0         (M1)

t=6.74416

=6.74 (sec)         A1

 

Note: Do not award A1 if additional values are given.

 

[2 marks]

a.

010vtdt  OR  -06.74416vtdt+6.744169.08837vtdt-9.0883710vtdt         (A1)

=37.0968

=37.1 m         A1

 

[2 marks]

b.

recognizing acceleration at t=7 is given by v'7         (M1)

acceleration =5.93430

=5.93 ms-2         A1

 

[2 marks]

c.
Examiners’ report
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