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19M.1.AHL.TZ2.H_2

pestleMathematicsAAHLPaper 119M· ahl-3-12-vector-definitionssource ↗

Three points in three-dimensional space have coordinates A(0, 0, 2), B(0, 2, 0) and C(3, 1, 0).

Find the vector  AB .

[1]
a.i.

Find the vector  AC .

[1]
a.ii.

Hence or otherwise, find the area of the triangle ABC.

[4]
b.
Markscheme / solution

AB = ( 0 2 2 )       A1

Note: Accept row vectors or equivalent.

[1 mark]

a.i.

AC = ( 3 1 2 )       A1

Note: Accept row vectors or equivalent.

[1 mark]

a.ii.

METHOD 1

attempt at vector product using  AB and  AC .      (M1)

±(2i + 6j +6k)      A1

attempt to use area  = 1 2 | AB × AC |        M1

= 76 2 ( = 19 )       A1

 

METHOD 2

attempt to use  AB AC = | AB | | AC | cos θ        M1

( 0 2 2 ) ( 3 1 2 ) = 0 2 + 2 2 + ( 2 ) 2 3 2 + 1 2 + ( 2 ) 2 cos θ

6 = 8 14 cos θ       A1

cos θ = 6 8 14 = 6 112

attempt to use area  = 1 2 | AB × AC | sin θ        M1

= 1 2 8 14 1 36 112 ( = 1 2 8 14 76 112 )

= 76 2 ( = 19 )       A1

[4 marks]

b.
Examiners’ report
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a.i.
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a.ii.
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b.