18N.1.SL.TZ0.T_11

pestleMathematicsAASLPaper 118N· sl-5-4-tangents-and-normalsource ↗

Consider the curve y = 5x³− 3x.

The curve has a tangent at the point P(−1, −2).

Find the equation of this tangent. Give your answer in the form y = mx + c.

Markscheme / solution

(y − (−2)) = 12 (x − (−1)) (M1)

−2 = 12(−1) + c (M1)

Note: Award (M1) for point and their gradient substituted into the equation of a line.

y = 12x + 10 (A1)(ft) (C2)

Note: Follow through from part (b).

[2 marks]

Examiners’ report

[N/A]