18M.2.AHL.TZ1.H_1
The 3rd term of an arithmetic sequence is 1407 and the 10th term is 1183.
Calculate the number of positive terms in the sequence.
Markscheme / solution
1471 + (n − 1)(−32) > 0 (M1)
⇒ n <
n < 46.96… (A1)
so 46 positive terms A1
[3 marks]
Examiners’ report
[N/A]