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18M.2.SL.TZ2.S_6

pestleMathematicsAISLPaper 218M· sl-2-5-modelling-functionssource ↗

At an amusement park, a Ferris wheel with diameter 111 metres rotates at a constant speed. The bottom of the wheel is k metres above the ground. A seat starts at the bottom of the wheel.

The wheel completes one revolution in 16 minutes.

After t minutes, the height of the seat above ground is given by h ( t ) = 61.5 + a cos ( π 8 t ) , for 0 ≤ t ≤ 32.

Find when the seat is 30 m above the ground for the third time.

Markscheme / solution

valid approach      (M1)
eg   sketch of h and  y = 30 , h = 30 , 61.5 55.5 cos ( π 8 t ) = 30 , t = 2.46307 , t = 13.5369

18.4630

t = 18.5 (minutes)      A1 N3

[3 marks]

Examiners’ report
[N/A]