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17M.2.AHL.TZ2.H_1

pestleMathematicsAIHLPaper 217M· sl-4-5-probability-concepts-expected-numberssource ↗

There are 75 players in a golf club who take part in a golf tournament. The scores obtained on the 18th hole are as shown in the following table.

M17/5/MATHL/HP2/ENG/TZ2/01

One of the players is chosen at random. Find the probability that this player’s score was 5 or more.

[2]
a.

Calculate the mean score.

[2]
b.
Markscheme / solution

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

P ( 5  or more ) = 29 75 ( = 0.387 )      (M1)A1

[2 marks]

a.

mean score = 2 × 3 + 3 × 15 + 4 × 28 + 5 × 17 + 6 × 9 + 7 × 3 75      (M1)

= 323 75 ( = 4.31 )      A1

[2 marks]

b.
Examiners’ report
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a.
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b.