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EXM.1.AHL.TZ0.42

pestleMathematicsAIHLPaper 1EXM· ahl-1-15-eigenvalues-and-eigenvectorssource ↗

Given the matrix A ( 3 2 1 0 ) find the values of the real number k for which det ( A k I ) = 0 where  I = ( 1 0 0 1 )

 

Markscheme / solution

det ( A k I ) = 0

| 3 k 2 1 k | = 0        (M1)

k 2 3 k + 2 = 0          (M1)

( k 2 ) ( k 1 ) = 0

k = 1 , 2          (A2)   (C4)

[4 marks]

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